94.8k views
1 vote
Given: ABCD is a parallelogram. Prove: ∠A and ∠D are supplementary. Parallelogram A B C D is shown. By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are angles. Because AB and DC are , the same-side interior angles must be by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.

User Thenoseman
by
6.3k points

2 Answers

3 votes

Answer:

1.same-side interior

2.parallel

3.supplemetary

Explanation:

Cause i got it right duh

User Lolade
by
6.5k points
3 votes

Answer:

AD is a transversal between these sides, so ∠A and ∠D are supplementary angles.

Explanation:

Supplementary angles are two or more angles that sum up to
180^(o). And a parallelogram has opposite side to be parallel and equal. With the sum of interior angles to be
360^(o).

Given that: AB∥DC

<A and <D are consecutive angles of the parallelogram.

AD is the transversal of the interior angles A and D, so that the addition of <A and <D gives the sum of angles on a straight line.

Therefore, AD is a transversal between these sides, so ∠A and ∠D are supplementary angles.

User Rsakhale
by
6.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.