Question

In the Bohr model of the hydrogen atom, an electron in the 2nd excited state moves at a speed of 5.48 105 m/s in a circular path of radius 2.12 10-10 m. What is the effective current associated with this orbiting electron

Answer 1

The current is
`I = 6.59*10^(-5) \ A`

Step-by-step explanation:

From the question we are told that

The speed is
`v = 5.48*10^(5) \ m/s`

The radius is
`r = 2.12 *10^(-10) \ m`

Generally the period of the orbiting electron is mathematically represented as

`T = (2 \pi * r )/(v)`

=>
`T = (2 * 3.142 * 2.12 *10^(-10) )/( 5.48 *10^(5))`

=>
`T = 2.43 *10^(-15) \ s`

Gnerally the effective current associated with this orbiting electron

`I = (e)/(T)`

Here e is the charge on an electron with value
`e = 1.60 *10^(-19) \ C`

So

`I = (1.60 *10^(-19))/(2.43 *10^(-15))`

=>
`I = 6.59*10^(-5) \ A`