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show answer No Attempt 50% Part (b) Calculate the non-relativistic speed of these electrons v in m/s.

User Arman H
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is
v = 9.18 *10^(6) \ m/s

Step-by-step explanation:

From question we are told that

The potential difference is
\Delta V = 0.24 kV = 0.24 *10^(3) \ V

Generally the the non-relativistic speed of these electrons is mathematically represented as


v = \sqrt{(2 * e * \Delta V)/(m) }

Here m is the mass of an electron with value
m = 9.11 *10^(-31 ) \ kg

e is the charge on an electron with value
e = 1.60 *10^(-19) \ C

So


v = \sqrt{(2 * 1.60 *10^(-19) * 0.24 *10^(3) )/(9.11*10^(-31)) }

=>
v = 9.18 *10^(6) \ m/s

User Nacho Coll
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