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If the breaking strength of the string is 120 N, what is the minimum angle the string can make with the horizontal

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Complete Question

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string, If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?

Answer:

The value is
\theta = 4.41^o

Step-by-step explanation:

From the question we are told that

The mass of the rock is
m_r = 940 \ g = 0.94 \ kg

The length of the string is
l = 1.30 \ m

The breaking strength(i.e the maximum tension) on the string is
T = 120 \ N

Gnerally the vertical component of the tension experienced by the string is mathematically represented as


T_v = T sin(\theta)

Generally this vertical component of tension is equivalent to the weight of the rock

So


Tsin (\theta) = mg

=>
\theta = sin^(-1) [(mg)/( T) ]

=>
\theta = sin^(-1) [(0.940 *9.8 )/( 120) ]

=>
\theta = 4.41^o

User Andrii  Filenko
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