The main part of the question is missing which is given as follows:
The genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in Drosophila. Phenotypically wild-type females (m + g / mg +) were mated to miniature-winged males with garnet eyes.
Answer:
The correct answer is - Miniature wings,
-garnet eyes
-Wild type
Step-by-step explanation:
Result of crossing over the result in two types of offspring that are either parental or recombinant offspring. Parental offsprings are the offspring with the phenotypic or genotypically similar.
Recombinant is generated due to the process of recombination or crossing over of sister chromatids during the formation of gamete.
A cross between m+g/mg+ female and mg/mg male, so the offspring would be:
Parental : mg+/mg
Parental : m+g/mg
Recombinant : mg/mg
Recombinant : m+g+/mg
As we know, Miniature wings,
-garnet eyes
-Wild type