Find the margin of error for a 90% confidence interval when the standard deviation is σ = 50 and n = 25. (Round to three decimal places.)

Question

asked Jun 26, 2021 207k views

1 Answer

Jan Hommes · Answer 1 · 2021-07-02T02:05:28+0000

Answer:

Margin of error = 16.5

Explanation:

The formula for the margin of error is given by :

$M=z* (\sigma)/(\sqrt n)$

We have, z (for 90% confidence interval) = 1.65

σ = 50 and n = 25

Putting all the values in the above formula, we get :

$M=1.65* \frac{50}{\sqrt {25}}\\\\M=16.5$

So, the margin of error for a 90% confidence interval is 16.5.