Answer:
Step-by-step explanation:
10.8 dm³ = 10.8 L
4.1 g of methane = 4.1 / 16 = .25625 moles
V₁ = 10.8 dm³
V₂ = 13.8 dm³
work done in isothermal expansion = 2.303 nRT log V₂ / V₁
= 2.303 x .25625 x 8.31 x 310 x log 13.8 / 10.8
= 1520.27 x log 1.2777
= 161.8 J.