Question

In a single-factor ANOVA problem involving four populations or treatments, the four sample standard deviations are 25.6, 30.4, 28.7, and 32.50. Then, the mean square for error is

Answer 1

MSE = 864.86

Explanation:

Four sample standard deviations are 25.6, 30.4, 28.7, and 32.50. We need to find the mean square for error. It can be calculated as follows :

Total no of observations, n = 4

`\text{MSE}=\frac{\text{SD}^2}{n}\\\\\text{Putting all the values, we get :}\\\\\text{MSE}=(25.6^2+30.4^2+28.7^2+32.5^2)/(4)\\\\\text{MSE}=864.86`

Hence, the mean square for error is 864.86.