Question

A sample of air is held in a 722 ml. container at 23.3°C. This sample is transferred into a 481 mL container

with a measured pressure of 2.055 atm and a stable temperature of 80.1. What was the initial pressure
in the first container (in atm)?
01.38
0.978
01.24
O 1.15

Answer 1

Apply combine gas law

• T1=296.3K
• T2=353K

So

`\\ \rm\Rrightarrow (P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`\\ \rm\Rrightarrow (P1(0.722))/(296.3)=(0.481(2.055))/(353)`

`\\ \rm\Rrightarrow 0.0024P1=0.0028`

`\\ \rm\Rrightarrow P_1=1.167atm`

D