Question

A bacterial blood infection is growing at a rate of 0.0013 cm3/hr, how many
L/day is this?

Answer 1

`Rate = 3.12 * 10^(-5)L/day`

Step-by-step explanation:

Given

`Rate =0.0013cm^3/hr`

Required

Convert to L/day

First, we convert the cm³ to L (litre)

`1cm^3 = 0.001L`

So:

`0.0013cm^3 = 0.0013 * 0.001L`

`0.0013cm^3 = 1.3 * 10^(-3) * 10^(-3)L`

`0.0013cm^3 = 1.3 * 10^(-6)L`

Solving further:

`1hr = (1)/(24)\ day`

Substitute these values in
`Rate =0.0013cm^3/hr`

`Rate =1.3 * 10^(-6)L/(1)/(24)\ day`

`Rate =1.3 * 10^(-6)L* (24)/(1 \ day)`

`Rate = 31.2 * 10^(-6)L/day`

`Rate = 3.12 * 10^(-5)L/day`