Answer:
The initial velocity of the ball is : 2.34 m/s
Step-by-step explanation:
Taking this case as a free fall where the ball falls a distance of 1 m in 0.75 seconds to reach the floor, the initial velocity is calculated as;
d= v₁*t + 0.5*a*t² ---------kinematic equation for displacement d where v₁ is the initial velocity, a is acceleration due to gravity and t is time.
Given in the question;
d= - 1 m -------negative sign means the displacement is downwards
a= - 9.8 m/s² ------for a free-falling
t= 0.75 s----------seconds for the ball to reach the floor
v₁ = initial velocity of the ball in m/s
Substitute real values in the formula as;
d= v₁*t + 0.5*a*t²
-1= v₁*0.75 + 0.5 * -9.8 *0.75²
-1=0.75v₁ -2.76 ----------solve for v₁ as;
-1+2.76 = 0.75 v₁
1.76 = 0.75 v₁
1.76/0.75 = 0.75 v₁/0.75
2.34 = v₁
The initial velocity of the ball is : 2.34 m/s