Answer:
Q = 0.05 [C]
Step-by-step explanation:
To be able to determine the load we must first determine the power by means of ohm's law:
P = V*I
where:
P = power [W]
V = volts [V]
I = amperes [amp]
P = 220*0.05
P = 11 [W]
Now as we have a power value, we know that power is defined as work in unit time, i.e. Joules over second is the equivalent of Watts.
P = w/t
where:
w = work [J]
t = time = 1 [s]
w = 11*1
w = 11 [J]
Finally, if we want to know how much charge was involved, we use:
Q = w/V
where:
Q = charge [coulumbs]
w = work = 11 [J]
V = volts = 220 [V]
Q = 11/220
Q = 0.05 [C]