Answer:
x=11
Explanation:
log(3x+1)+log12−log(2x−5)=0 , solve for x∈R
log(3x+1)+log(2−1)−log(2x−5)=0
log(3x+1)−log2−log(2x−5)=0
log3x+12−log(2x−5)=0
log3x+122x−5=0
log(3x+12×12x−5)=0
log3x+14x−10=0
e0=3x+14x−10
4x−10=3x+1
x = 11
5.3m questions
6.8m answers