9514 1404 393
Answer:
18050 square feet
Explanation:
Let x represent the length of fence parallel to the creek. Then the remaining 380-x feet of fence is divided between the two ends of the pasture. The area will be the product ...
A = (x)(1/2)(380 -x)
The graph of this is a parabola that opens downward. It has x-intercepts at x=0 and x=380. The vertex (maximum) will be on the line of symmetry, halfway between these zeros, at x = (0 +380)/2 = 190.
Then the area is ...
A = (190 ft)(1/2)(380 -190 ft) = (190 ft²)/2 = 18,050 ft²
The maximum possible area of the pasture is 18,050 square feet.