Question

If the distance of an object is determined from the relation: d = a X + b Y Where: (d) is the distance covered by the body. (a) is a physical quantity which has a dimensions (L T^-1). (b) Is a physical quantity which has a dimensions (L T^-2). So: *

The dimension formula of (X) is T and that of (Y) is T^2.

The dimension formula of (X) is T and that of (Y) is T^-2

The dimension formula of (X) is T^-1 and that of (Y) is T^2.

The dimension formula of (X) is T^-1 and that of (Y) is T^-2.​

Answer 1

The dimension formula of X is T and that of Y is T^2

Step-by-step explanation:

d = aX + bY is ACTAULLY
`S = V_(i) t + (1)/(2) a t^(2)`

so v = LT^-1

t = T

numerics do not have any dimensional formula so ignore
`(1)/(2)`

a = LT^-2

t = T^2

So answer for x is T and y T^2