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Points J, K, and L are collinear one, and JL: LK = J is located at (-3,5), K is located at (1,-10) and Lis located at (x, y). What are the values of x and y?​

Points J, K, and L are collinear one, and JL: LK = J is located at (-3,5), K is located-example-1

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Answer:

L = (x, y) = (1/5, -7)

Explanation:

The given relation tells you ...

(L -J)/(K -L) = 4/1

Cross-multiplying, we have ...

L -J = 4(K -L)

5L = 4K +J . . . . add 4L+J

L = (4K +J)/5

L = (4(1, -10) +(-3, 5))/5 = (4-3, -40+5)/5

L = (x, y) = (1/5, -7)

Points J, K, and L are collinear one, and JL: LK = J is located at (-3,5), K is located-example-1
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