The resultant force is
→F=321.9N at−165.4°
The equilibrant is
→Feq=321.9N at14.6°
Step-by-step explanation:
This problem requires that we resolve the force vectors into x- and y-components.
Once this is done, we can add the components easily, as the one 2-dimensional problem will be two 1-dimensional problems.
Finally, we will convert the resultant force into standard form and find the equilibrant.
Resolve into components:
F1x=F1cos180°=215(−1)=−215N
F1y=F1sin180°=0N
F2x=F2cos(−140°)=126(−0.766)=−96.5N
F1y=F1sin(−140°)=126(−0.643)=−81.0N
Note the change of the angle used to give the direction of F2. Standard angles (rotation from the x-axis; counterclockwise is +) should be used to avoid sign errors in the results.
Now, we add the components:
Fx=F1x+F2x=−311.5N
Fy=F1y+F2y=−81.0N
Technically, this is the resultant force. However, it should be changed back into standard form. Here's how:
F=√(