Answer:
![22.91^\circ, 202.91^\circ](https://img.qammunity.org/2021/formulas/mathematics/high-school/ppab5lc46auv4sqxlqe1ppb3tnalikv3oc.png)
Explanation:
Given that:
![tan\theta=0.4226](https://img.qammunity.org/2021/formulas/mathematics/high-school/636jjpteav3h4kudxjuqwqdtqn7dawaj0g.png)
To find:
The two values of
![\theta = ?](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7zdyn4nftnujoc47lkh90ffg167rtb0sbl.png)
Solution:
By given equation:
![\theta = tan^(-1)(0.4226)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8cq39lj0r59h4g0pwa75bjz6ixom0dn47h.png)
can be equal to
![\approx 20.91^\circ](https://img.qammunity.org/2021/formulas/mathematics/high-school/6fx45g7y20n1ent72wzd3rbc6hiblekl9x.png)
Also, we know the property that,
is positive in the 3rd quadrant.
and following is also true:
![tan\theta = tan(180^\circ+\theta)](https://img.qammunity.org/2021/formulas/mathematics/high-school/s2tlu0xclvq818wkn5xb4hcpbxd89qyhbx.png)
Therefore, another value possible for
can be:
![\theta =180^\circ+22.91\\\Rightarrow \theta \approx 202.91^\circ](https://img.qammunity.org/2021/formulas/mathematics/high-school/t70jybooj0plb1ifgcxzup4jt3cpzsotxc.png)
Therefore, the answer is:
![22.91^\circ, 202.91^\circ](https://img.qammunity.org/2021/formulas/mathematics/high-school/ppab5lc46auv4sqxlqe1ppb3tnalikv3oc.png)