Question

What amount of hydrogen gas would be necessary to to produce 14.0 mol NH3(g)(assuming there is enough nitrogen gas to complete the reaction)?

Answer 1

Amount of hydrogen gas needed 42 g.

Step-by-step explanation:

Given data:

Amount of ammonia produced = 14.0 mol

Amount of hydrogen gas needed = ?

Amount of nitrogen = excess

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Now we will compare the moles of hydrogen with ammonia.

NH₃ : H₂

2 : 3

14.0 : 3/2×14.0 = 21 mol

Mass of hydrogen needed:

Mass = number of moles × molar mass

Mass = 21 mol × 2 g/mol

Mass = 42 g