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Write an equation of the line in slope-intercept form.

Write an equation of the line in slope-intercept form.-example-1
User Cjs
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Answer:


\displaystyle y=(1)/(3)x+(4)/(3)

Explanation:

Equation of a line

The slope-intercept form of a line is:

y=mx+b

Where m is the slope and b is the y-intercept.

Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated as follows:


\displaystyle m=(y_2-y_1)/(x_2-x_1)

Two points are given: (-4,0) (2,2). Calculate the slope:


\displaystyle m=(2-0)/(2+4)=(2)/(6)=(1)/(3)

We'll use the point-slope form of the line:

y-k=m(x-h)

Take the point (2,2):


\displaystyle y-2=(1)/(3)(x-2)

Operating:


\displaystyle y-2=(1)/(3)x-(2)/(3)

Adding 2:


\displaystyle y=(1)/(3)x-(2)/(3)+2

Operating, we get the slope-intercept form:


\boxed{\displaystyle y=(1)/(3)x+(4)/(3)}

User ChrisFro
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