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Review the incomplete derivation of the cosine sum identity.

A 2-column table with 5 rows. Column 1 has entries step 1, step 2, step 3, step 4, step 5. Column 2 has entries cosine (x + y), sine (StartFraction pi Over 2 EndFraction minus (x + y) ), blank, sine (StartFraction pi Over 2 EndFraction minus x) cosine (negative y) + cosine (StartFraction pi Over 2 EndFraction minus x) sine (negative y), blank.

Which expressions for Step 3 and Step 5 complete the derivation?

Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) + y )
Step 5: cos(x)cos(y) + sin(x)sin(y)
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) + y )
Step 5: cos(x)cos(y) – sin(x)sin(y)
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) minus y )
Step 5: cos(x)cos(y) + sin(x)sin(y)
Step 3: Sine ( (StartFraction pi over 2 EndFraction minus x) minus y )
Step 5: cos(x)cos(y) – sin(x)sin(y)

Review the incomplete derivation of the cosine sum identity. A 2-column table with-example-1
User Bskaggs
by
4.4k points

2 Answers

4 votes

Answer:

D

Explanation:

Top Answer was right, don't know why it was rated poorly

Review the incomplete derivation of the cosine sum identity. A 2-column table with-example-1
User Dpkstr
by
5.5k points
6 votes

Answer:

Option (4)

Explanation:

STEP - 1

cos(x + y)

STEP - 2


\text{sin}[(\pi)/(2)-(x+y)]

STEP - 3


\text{sin}[((\pi)/(2)-x)-y]

STEP - 4


\text{sin}((\pi)/(2)-x)\text{cos}(-y)+\text{cos}((\pi)/(2)-x)\text{sin}(-y)

STEP - 5

cos(x)cos(y) - sin(x)sin(y)

[Since,
\text{sin}((\pi)/(2)-x)=cos(x) and
\text{cos}((\pi)/(2)-x)=\text{sin}(x)]

[Since, cos(-x) = cos(x) and sin(-x) = -sin(x)]

Therefore, Option (4) will be the correct option.

User Aretor
by
5.3k points
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