28.1k views
3 votes
If tan m = One-half and tan n = –6, what is the exact value of tan(m + n)?

Negative StartFraction 11 Over 2 EndFraction
Negative StartFraction 11 Over 8 EndFraction
StartFraction 11 Over 8 EndFraction
StartFraction 11 Over 4 EndFraction

If tan m = One-half and tan n = –6, what is the exact value of tan(m + n)? Negative-example-1

2 Answers

3 votes

Answer:

B) -11/8

Explanation:

its correct on edge

User Iammehrabalam
by
7.1k points
5 votes

Answer:

B. -11/8

Explanation:

Given:

tan m = ½

tan n = -6

Required:

Exact value of tan(m + n)

Solution:

Find m and n:


tan (m) = (1)/(2)


tan (m) = 0.5


m = tan^(-1)(0.5)

m = 26° (approximated)


tan (n) = -6


n = tan^(-1)(-6)

n = -80° = 280° (i.e. 360 - 80)

Exact value of tan(m + n) = tan(26 + 280)

tan(306)

tan(307) = -1.37638192 ≈ -11/8

User Joymaker
by
6.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.