Question

A set of three resistors are set up in parallel. The resistor values are R1 = 3.0 Ohms, R2 = 11.0 Ohms, and R3 = 7.5 Ohms.

What is the total resistance of this circuit?

Answer 1

The total resistance in the circuit is 1.79 ohms

Step-by-step explanation:

Given;

first resistor, R1 = 3.0 ohms

second resistor, R2 = 11.0 ohms

third resistor, R3 = 7.5 ohms

The total resistance in the circuit is given by;

`(1)/(C_T) = (1)/(R_1) + (1)/(R_2) + (1)/(R_3)\\\\(1)/(C_T) =(R_2R_3 + R_1R_3+R_1R_2)/(R_1R_2R_3) \\\\ C_T = (R_1R_2R_3)/(R_2R_3 + R_1R_3+R_1R_2)\\\\ C_T = ((3*11*7.5))/((11*7.5) + (3*7.5)+(3*11))\\\\C_T = (247.5)/(138)\\\\C_T = 1.79 \ ohms`

Therefore, the total resistance in the circuit is 1.79 ohms