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The solution for x^2+2x+8<0_ is
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The solution for x^2+2x+8<0_ is

User Andrew Wynham
by
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1 Answer

5 votes

Answer:

Explanation:

x

2

−2x−8=0

x

2

−4x+2x−8=0

x(x−4)+2(x−4)=0

(x+2)(x−4)=0

⟹x=−2,4

User Eric Speelman
by
5.6k points
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