Remember that i = √(-1), so that
• i ² = -1,
• i ³ = i x i ² = i x (-1) = -i
• i ⁴ = i x i ³ = i x (-i) = -i ² = -(-1) = 1
Multiplying by i again gives i ⁵ = i and the cycle starts over.
The main observation to make here is that raising i to any multiple of 4 returns 1. So,
i ⁴⁸ = (i ⁴)¹² = 1¹² = 1
i ²²³ = i ²²⁰⁺³ = i ²²⁰ x i ³ = (i ⁴)⁵⁵ x i ³ = 1⁵⁵ x (-i) = -i
i ¹¹³ = i ¹¹²⁺¹ = i ¹¹² x i = (i ⁴)²⁸ x i = 1²⁸ x i = i
i ⁸² = i ⁸⁰⁺² = i ⁸⁰ x i ² = (i ⁴)²⁰ x i ² = 1²⁰ x (-1) = -1