Question

Solve: (step by step please)
x^2+9x+9=0

Answer 1

X1= -9-3
`\sqrt5` over 2 X2= -9+3
`\sqrt5` over 2 (draw a line under the -9 to the 5

and put a 2 under like a fraction

i cant get the line all the way

across on here sorry

Step by step explanation:

x= -9
`\sqrt9^2 -4x1x9` Over (draw a line under that) Put all that under sq root

2 x 1 also

x= -9+
`\sqrt81-36` Over 2

2

x= -9 +
`\sqrt45` Over 2

2

x=-9 +3
`\sqrt5` Over 2

2

separate solutions gives your answer above

Also ......note ..... put a line under each + sign ok I worked hard getting this all down best i can

Answer 2

`x=(-9\pm3√(5) )/(2)`

Explanation:

Standard Form: ax² + bx + c = 0

Quadratic Formula:
`x=(-b\pm√(b^2-4ac) )/(2a)`

Step 1: Write equation

x² + 9x + 9 = 0

Since we cannot factor the expression, we will have to use the quadratic formula.

Step 2: Define

a = 1

b = 9

c = 9

Step 3: Solve for x

1. Substitute:
   `x=(-9\pm√(9^2-4(1)(9)) )/(2(1))`
2. Evaluate:
   `x=(-9\pm√(81-36) )/(2)`
3. Evaluate:
   `x=(-9\pm√(45) )/(2)`
4. Simplify:
   `x=(-9\pm3√(5) )/(2)`