Question

How to do this question plz ​

Answer 1

`A = 50cm {}^(2)`

Explanation:

`let \: the \: two \: sides \: be : \\ p = 10 \: cm \\ q = x \: cm \: (yet \: unknown) \\ then \: the \: area,\: \boxed{A} \: is \: given \: by : \\ A = (1)/(2) pq = (1)/(2) 10 * q. \\ so \: lets \: find \: q : \\ if \: we \: bisect \: the \: rhombus, \: then \: applying \: the \: laws \: of \: sum \: of \: angles : \\ 180 - (80 + 50) = 50. \\ applying \: the \: sin \: rule : \\ ( \sin(50) )/(10) = ( \sin(50) )/(q) \\ \\ q \sin(50 ) = 10 \sin(50) \\ q = (10 \sin(50) )/( \sin(50) ) \\ q = 10. \\ ......wait....what {?} \: all \: of \: this \: to \: just \: to \\ \: know \: that \: q = 10. \\ so \: \\ A = (1)/(2) pq = (1)/(2) * 10 * 10 \\ A = 50cm {}^(2)`

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