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Calculate the frequency of visible light having a wavelength of 4461nm

User Shimy
by
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1 Answer

6 votes

Answer:

f = 6.7 × 10^13 Hz.

Step-by-step explanation:

c= f × lambda [sorry..could not find the symbol]

Given,

c= 3 ×10^8 m/s

lambda= 4461nm = 4461 ×10^-9 m

f = c ÷ lambda

f= (3.0 × 10^8) ÷ (4461 × 10^-9)

f = 6.7 × 10^13 Hz.

User Mohsin Sethi
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4.1k points