Volume (in L) of Carbon dioxide : 23.6 L
Further explanation
Avogadro's hypothesis:
In the same T,P and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
![\tt (V_1)/(n_1)=(V_2)/(n_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/hxv8c299p9immd0ilgyv7hpdr1ksa37et0.png)
Combustion of ethane :
![\tt 2C_2H_6+7O_2\Rightarrow 4CO_2+6H_2O](https://img.qammunity.org/2021/formulas/chemistry/high-school/ret7mov3l30reu2gmn00ql5xlb1mye0qja.png)
mol ratio of C₂H₆ : CO₂ ⇒ 2 : 4
so the volume of CO₂ :
![\tt (V_1)/(n_1)=(V_2)/(n_2)\\\\(11.8)/(2)=(V_2)/(4)\\\\V_2=\boxed{\bold{23.6~L}}](https://img.qammunity.org/2021/formulas/chemistry/high-school/kq3qomi0kyyciztwn704o6sq0zrxt3ab9c.png)