Answer:
Cu²⁺(aq) + S²(aq)⁻ → CuS(s)
Molarity = 0.88 M
Step-by-step explanation:
Chemical equation:
Cu(NO₃)₂(aq) + Li₂S(aq) → 2LiNO₃(aq) + CuS(s)
Ionic equation:
Cu²⁺(aq) + 2NO₃(aq)⁻ + 2Li⁺(aq) + S²(aq)⁻ → 2Li⁺(aq) + 2NO₃⁻(aq) + CuS(s)
Net ionic equation:
Cu²⁺(aq) + S²(aq)⁻ → CuS(s)
2)
Given data:
Mass of KBr = 170 g
Volume of solution = 1625 mL (1625 /1000 = 1.625 L)
Molarity of solution = ?
Solution:
First of all we will calculate the number of moles of KBr.
Number of moles = mass/molar mass
Number of moles = 170 g/ 119 g/mol
Number of moles = 1.43 mol
Molarity of solution:
Molarity = number of moles / Volume of solution in L
Now we will put the values.
Molarity = 1.43 mol/ 1.625 L
Molarity = 0.88 M