Question

John is four times as old as Jill.Bob is two years younger than John. The sum of their ages is 34.How old is each person?

Answer 1

`john \: is \: 16 \: yrs \: old \\ bob \: is \: 14 \: yrs \: old \\ jill \: is \: 4 \: yrs \: old`

Explanation:

`let \: johns \: age \: = j(a) \\ let \: jills \: age \: = ji(a) \\ let \: bobs \: age \: = b(a) \\ then \\ j(a) = 4 * ji(a) \: \\ and \\ \: \: b(a) = (4 * ji(a) )- 2 \\ if \: ji(a) + j(a) + b(a) = 34. \: then \\ ji(a) + (4 * ji(a)) + (4 * ji(a)) - 2= 34. \\ so : \\ ji(a) = (34)/(9) = 4. \\ j(a) = 4 * 4 = 16. \\ b(a) = 16 - 2 = 14.`

Answer 2

John is 16 years old Bob is 14 and Jill is 4 years old.

Explanation:

let the age of Jill be x.

According to question,

John= 4x

Bob= 4x- 2

Given, the sum of ages is 34

Now,

4x+x+(4x-2) = 34

or, 9x= 36

or, x= 36\ 9

x= 4

Therefore, the age of john=4*4=16 year

BOB = 4*4-2=14 years

Jill = x= 4 years