Answer:The greatest possible number of red sweets is 28
Step-by-step explanation:
Let the common ratio between blue and red sweets be x
Then,
Number of blue sweets = 2x
Number of green sweets = 7x
If the common ratio between the green and red sweets be y
Then,
Number of green sweets = 3y
Number of red sweets = y
Here the number of green sweets must be equal
Therefore,
Also the sum of all of them is 140
Thus,
x should be a whole number
Therefore,
And the sum of all the sweets will be 136
Therefore,
Thus the greatest possible number of red sweets is 28
Hope this helps.