Question

A ball is shot horizontally at 17.3m/s from the roof of a building 55.2 m tall, (use g = 9.8 m/s ^ 2) How far from the base of the building does the ball land?

Answer 1

Given that,

The initial speed of a ball, u = 17.3 m/s

It is shot from the roof of a 52 m tall building, h = 52 m

It is required to find the distance from the base of the building the ball land. Let the distance be d.

Final velocity of the ball, v = 0 (when it lands)

We can use third equation of motion to find it.

`v^2-u^2=2ad`

a = -g

`-u^2=-2gd\\\\d=(u^2)/(2g)\\\\d=((17.3)^2)/(2* 9.8)\\\\d=15.26\ m`

So, it will land at a distance of 15.26 m.