Question

Harry is planning a trip by air. He has to choose the cheaper of two airlines. Airline A charges $50 for a ticket and $25 per bag of luggage. Airline B charges $30 for a ticket and $30 per bag of luggage. Harry determines that, given his number of suitcases, the two airlines are equivalent in terms of cost. How much will it cost? How many suitcases did he have?

Answer 1

4 luggage cases and it will cost $150.00

Explanation:

We can assume that ticket cost is a constant as long as no one else is flying with him. We take both equations and make them a systems of equtions by making both equations equivalent. (25x+50) = (30x+30). Subtracting 25x from the second equation and 30 from the first, we get 5x = 20. Dividing by 5 on both sides gives you x=4 which is how much luggage he will have. Then take 4 and plug x in for both equations and you get $150 on both.

Answer 2

Harry has 4 suitcases and it will costs $150!

Explanation:

First we have to put the terms we know into an equation.

Airline A : $50 + $25x = t

Airline B : $30 + $30x = t

Now, we can input numbers into our variables in a table.

Airline A Airline B

1 50 + 25(1) = 65 30 + 30(1) = 60

2 50 + 25(2) = 100 30 + 30(2) = 90

3 50 + 25(3) = 125 30 + 30(3) = 120

4 50 + 25(4) = 150 30 + 30(4) = 150

So, from this info we know that Harry has 4 suitcases and it will costs $150!

Hope this Helps! :)

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-SGO