Question

SA = 2πr2 + 2nrh

(Use 3.14 for pi.)
Jill needs wrapping paper
for a cylindrical gift that is
10 inches high and measures
4 inches across the base.
How much wrapping paper
will she need?
square inches
Do NOT round your answer.

Answer 1

Answer: 150.72 square inches

Work Shown:

`\text{SA} = 2\pi*r^2 + 2\pi*r*h\\\\\text{SA} \approx 2*3.14*2^2 + 2*3.14*2*10\\\\\text{SA} \approx 150.72\\\\`

She'll need approximately 150.72 square inches of wrapping paper.

Note: The circular base is 4 inches across, which is the diameter. Cut this in half to get r = d/2 = 4/2 = 2 inches for the radius.