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What is an equation of the line that passes through the points (-6,-3) and (-3,-5) ?​

1 Answer

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Answer:

y = -2/3 x - 7

Explanation:

Solve for the slope first:

m = (y2 - y1) / (x2 - x1)

= [(-5) - (-3)] / [(-3) - (-6)]

= (-5 + 3) / (-3 + 6)

= -2 / 3

Use any of the ordered pairs to find the value of b: (-6, -3)

y = mx + b

-3 = (-2/3)(-6) + b

-3 = 12/3 + b

-3 = 4 + b

-3 - 4 = b

-7 = b

To find the equation of the line substitute the b value and the slope.

y = mx + b

y = -2/3 x - 7

User Derek Nguyen
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