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Y= x^2-4x+2 what is the vertex

User VirtualValentin
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\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{-4}x\stackrel{\stackrel{c}{\downarrow }}{+2} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ -4}{2(1)}~~~~ ,~~~~ 2-\cfrac{ (-4)^2}{4(1)}\right)\implies (2~~,~~2-4)\implies (2~~,~~-2)

User Sirus
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