Question

How would I find the inverse for

f(x) = 2/5(x-2)+1?​

Answer 1

The inverse is 5/2(x-1) +2

Explanation:

f(x) = 2/5(x-2)+1

Rewriting

y = 2/5(x-2)+1

Exchange x and y

x = 2/5(y-2)+1

Solve for y

Subtract 1 from each side

x-1 = 2/5(y-2)+1-1

x-1 = 2/5(y-2)

Multiply each side by 5/2

5/2(x-1) = 5/2 (2/5)(y-2)

5/2(x-1) = (y-2)

Add 2 to each side

5/2(x-1) +2 = y-2+2

5/2(x-1) +2 = y

The inverse is 5/2(x-1) +2