Question

(2x^4 + 4x^3-8) + (x^2- 2)​

Answer 1

2x^4+4x^3+x^2-10

`2x^4+4x^3+x^2-10`

Explanation:

`(2x^4 + 4x^3-8) + (x^2- 2)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=2x^4+4x^3-8+x^2-2\\\\\mathrm{Group\:like\:terms}\\\\=2x^4+4x^3+x^2-8-2\\\\\mathrm{Subtract\:the\:numbers:}\:-8-2=-10\\\\=2x^4+4x^3+x^2-10`

If you meant to put the division sign ;

`(\left(2x^4+4x^3-8\right))/(\left(x^2-2\right))\\\\Divide\:\: (\left2x^4+4x^3-8\right)/(\left x^2-2\right) \: : \: 2x^2+(4x^3+4x^2-8)/(x^2-2)\\\\=2x^2+(4x^3+4x^2-8)/(x^2-2)\\\\Divide \: \:(4x^3+4x^2-8)/(x^2-2) : \:(4x^2+8x-8)/(x^2-2)\\=2x^2+4x+(4x^2+8x-8)/(x^2-2)\\\\Divide\\\\=2x^2+4x+4+(8x)/(x^2-2)`

Answer 2

Answer: 0 i think

Explanation: