148k views
4 votes
(2x^4 + 4x^3-8) + (x^2- 2)​

User Bstahlhood
by
7.8k points

2 Answers

7 votes

Answer:

2x^4+4x^3+x^2-10


2x^4+4x^3+x^2-10

Explanation:


(2x^4 + 4x^3-8) + (x^2- 2)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=2x^4+4x^3-8+x^2-2\\\\\mathrm{Group\:like\:terms}\\\\=2x^4+4x^3+x^2-8-2\\\\\mathrm{Subtract\:the\:numbers:}\:-8-2=-10\\\\=2x^4+4x^3+x^2-10

If you meant to put the division sign ;


(\left(2x^4+4x^3-8\right))/(\left(x^2-2\right))\\\\Divide\:\: (\left2x^4+4x^3-8\right)/(\left x^2-2\right) \: : \: 2x^2+(4x^3+4x^2-8)/(x^2-2)\\\\=2x^2+(4x^3+4x^2-8)/(x^2-2)\\\\Divide \: \:(4x^3+4x^2-8)/(x^2-2) : \:(4x^2+8x-8)/(x^2-2)\\=2x^2+4x+(4x^2+8x-8)/(x^2-2)\\\\Divide\\\\=2x^2+4x+4+(8x)/(x^2-2)

User Nubaslon
by
8.7k points
5 votes

Answer: 0 i think

Explanation:

User Kausty
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories