So you just need to find the pairs that work in when you substitute them in, we can go through them one by one.
When you have
(2,-3) x= 2 and y = -3 so if we put this into the equation you get
(3x2) -(2x-3) which is 6–6 which is 6+6 which is 12, so this coordinate is CORRECT
(4,0)
X= 4, y =0
(3x4) - (3x0) = 12 so is CORRECT
(5,-1)
X= 5 y = -1
(3x5) - (2x-1) = 15- -2 = 15+2 = 17 so is INCORRECT
(0,-6)
X= 0 y= -6
(3x0) - (2x -6) = 0- -12 = 0 + 12 = 12 so is CORRECT
(2,3)
X = 2, y=3
(3x2)- 2x3 = 6-6 = 0 so is INCORRECT
Hope this helps, let me know if you have any questions