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Prove that the equation 12x2+70x+a2+1=0 for any value of a does not have any positive roots. I need help ASAP! Please someone Help

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4 votes

Answer:

The solution follows below

Explanation:

12·x²+70·x+a²+1=0

Let's find the discriminant

D=4900-12*4*(a²+1)=4900-48(a²+1) <4900 for any a

So √D<70 (1) for any a

first root X1= (-70-√D)/24<0 so -70-√D<0

second root x2=(-70+√D)/24<0 so -70+√D<0 (√D<70 look to inequality (1))

=> Both roots are negative for any a.

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