Question

Plz help need this last question

Answer 1

a = -√3/3

b = 2√3/3

Explanation:

Finding the slope of the tangent at C by finding the derivative:

x^2 + y^2 = 1

2x + 2y y' = 0

2y y' = -2x

y' = -2x / 2y = -x/y

So the slope = - 1/2 / √3/2

= -1/2 * 2/√3

= -1/√3

= -√3/3

Using the point-slope form of a straight line

y - y1 = m(x - x1)

y - √3/2 = -√3/3(x - 1/2)

y - √3/2 = -√3/3 x +√3/6

y = -√3/3 x + √3/6 +√3/2

y = -√3/3 x + 4√3/6

y = -√3/3x + 2√3/3