Question

MQ = 2x+2
QO= 3x-10

find x

(it’s a rhombus)

Answer 1

x = 12

Explanation:

The diagonals PN and MO are perpendicular bisectors of each other, thus

QO = MQ , substitute values

3x - 10 = 2x + 2 ( subtract 2x from both sides )

x - 10 = 2 ( add 10 to both sides )

x = 12

Answer 2

2x+2=3x-10

2+10=3x-2x

x= 12