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Which of the following is the complete list of roots for the polynomial function f (x) = (x squared + 6 x + 8) (x squared + 6 x + 13)?

2 Answers

7 votes


( {x}^(2) + 6x + 8)( {x}^(2) + 6x + 13) =0 \\

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{x}^(2) + 6x + 8 = 0


(x + 2)(x + 4) = 0

##############################


x + 2 = 0


x = - 2

##############################


x + 4 = 0


x = - 4

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{x}^(2) + 6x + 13 = 0


∆ = {b}^(2) - 4ac


a = coefficient \: \: of \: \: {x}^(2) = 1


b = coefficient \: \: of \: \: x = 6


c = the \: \: alone \: \: number \: = 13 \\

Thus ;


∆ = ({6})^(2) - 4 * (2) * (13)


∆ = 36 - 104


∆ = - 68

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Point :

Remember from now on ,

In quadratic functions ;

if :


∆ > 0

The function has two roots

if :


∆ = 0

The function has just one root

if :


∆ < 0

The function doesn't have any root.

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Thus , ( + 6x + 13 ) doesn't have any root.

So ; ( x = - 2 ) & ( x = - 4 ) are the only roots.

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And we're done....♥️♥️♥️♥️♥️

User DanielRICADO
by
5.0k points
5 votes

Answer:

c)-2,-4,-3+2i,-3-2i

Explanation:

edge2020

User Uygar Y
by
5.2k points