Question

2. A motorcycle starts at rest and moves a distance of 350 m. If it has a constant acceleration of 4.55m/s2, what is

its final velocity?

Answer 1

Vf = ≈56.436 m/s

Step-by-step explanation:

We'll need to use the equation:

Vf^2 = Vi^2 + 2aΔx

Plugging in what we know, we get:

Vf^2 = (0)^2 + 2(4.55)(350)

Finally, some algebra:

Vf^2 = 3185

Vf = ≈56.436