Question 1

Find the mistake in the problem and explain why it is wrong

Question 2

$\sf x^2 - 3x - 8 = 4$

$\longrightarrow \sf x^2 - 3x - 8 - 4 = 0$

$\longrightarrow \sf x^2 - 3x - {\red{12}} = 0$

You had written (-4) instead of (-12)

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Quadratic formula:-

$\boxed{\sf{Roots = (-b \pm √(b^2 - 4ac))/(2a)}}$

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Here,

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By using quadratic formula,

$\sf{ x_1 = (-(-3) + √((-3)^2 - 4(1)(-12)))/(2(1))}$

$\leadsto \underline{\boxed{\mathfrak{ \pink{x_1 = (3 + √(57))/(2)}}}}$

Similarly,

$\sf x_2 = (-(-3) - √((-3)^2 - 4(1)(-12)))/(2(1))$

$\leadsto \underline{\boxed{\mathfrak{\pink{ x_2 = (3 - √(57))/(2)}}}}$

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