Question

What are the solutions to this quadratic equation?

x2+13=8x+37

Answer 1

x = 4 + 2 sqrt(10) or x = 4 - 2 sqrt(10)

Explanation:

Solve for x over the real numbers:

x^2 + 13 = 8 x + 37

Subtract 8 x + 37 from both sides:

x^2 - 8 x - 24 = 0

Add 24 to both sides:

x^2 - 8 x = 24

Add 16 to both sides:

x^2 - 8 x + 16 = 40

Write the left hand side as a square:

(x - 4)^2 = 40

Take the square root of both sides:

x - 4 = 2 sqrt(10) or x - 4 = -2 sqrt(10)

Add 4 to both sides:

x = 4 + 2 sqrt(10) or x - 4 = -2 sqrt(10)

Add 4 to both sides:

Answer: x = 4 + 2 sqrt(10) or x = 4 - 2 sqrt(10)