131k views
0 votes
The value of E for a system that performs 120 kJ of work on its surroundings and gains 50kJ of heat is ___?

User Chester
by
5.1k points

1 Answer

4 votes

Answer:

-70

Step-by-step explanation:

work is being done, so 120 will be negative, heat is being gained, so 50 will be positive.

Delta E = -120 + 50 = -70 kJ

User Celdor
by
5.9k points