Answer:
Yes, the ball will go over the goal post by 0.769 meters
Step-by-step explanation:
The given parameters are;
The height of the goalpost = 3.05 meters
The distance of the kicker from the goal post = 36 meters
The speed with which the ball is kicked, v = 20 m/s
The direction/path of the ball, θ = 53°
Therefore, we have;
The vertical component of the velocity,
= v × sin(θ) = 20 × sin(53°) ≈ 15.973 m/s
The horizontal component of the velocity, vₓ = v × cos(θ) = 20 × cos(53°) ≈ 12.036 m/s
The time, t. to reach the goal post with the horizontal velocity is given as follows;
Time = Distance/Velocity = 36/12.036 ≈ 3 seconds
The height. h. of the ball at 3 seconds is given as follows;
h =
× t - 1/2 × g × t²
h(3) = 15.973 × 3 - 1/2 × 9.8 × 3² = 3.819 m
The time to maximum height, is given as follows;
v = u - g·t
v = 0
u = 15.973 m/s
∴ u = g·t
15.973 = 9.8× t
t = 15.973/9.8 ≈ 1.63 seconds
Total time the ball stays in the air = 2 × 1.63 ≈ 3.26 seconds
Therefore, the ball is in the air at 3 seconds, and it will go over the goal post by 3.819 m- 3.05 m = 0.769 meters