Question

How to solve this problem???

Answer 1

`\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ \underset{\textit{we'll use this one}}{log_a a^x = x}\qquad \qquad a^(log_a x)=x \end{array} \\\\[-0.35em] ~\dotfill\\\\ 2.7e^x-5 ~~ = ~~33.6\implies 2.7e^x~~ = ~~38.6\implies e^x=\cfrac{38.6}{2.7} \\\\\\ \log_e(e^x)=\log_e\left( \cfrac{38.6}{2.7} \right)\implies x=\ln\left( \cfrac{38.6}{2.7} \right)\implies x\approx 2.66`